Solve (s+1+j3)(s+1-j3)

$$( s + 1 + j 3 ) ( s + 1 - j 3 )$$

Evaluate

$$\left(s+1\right)^{2}-j_{3}^{2}$$

Solution Steps

Apply the distributive property by multiplying each term of s+1+j_{3} by each term of s+1-j_{3}.

$$s^{2}+s-sj_{3}+s+1-j_{3}+j_{3}s+j_{3}-j_{3}^{2}$$

Combine s and s to get 2s.

$$s^{2}+2s-sj_{3}+1-j_{3}+j_{3}s+j_{3}-j_{3}^{2}$$

Combine -sj_{3} and j_{3}s to get 0.

$$s^{2}+2s+1-j_{3}+j_{3}-j_{3}^{2}$$

Combine -j_{3} and j_{3} to get 0.

$$s^{2}+2s+1-j_{3}^{2}$$

Expand

$$s^{2}+2s-j_{3}^{2}+1$$

Solution Steps

Apply the distributive property by multiplying each term of s+1+j_{3} by each term of s+1-j_{3}.

$$s^{2}+s-sj_{3}+s+1-j_{3}+j_{3}s+j_{3}-j_{3}^{2}$$

Combine s and s to get 2s.

$$s^{2}+2s-sj_{3}+1-j_{3}+j_{3}s+j_{3}-j_{3}^{2}$$

Combine -sj_{3} and j_{3}s to get 0.

$$s^{2}+2s+1-j_{3}+j_{3}-j_{3}^{2}$$

Combine -j_{3} and j_{3} to get 0.

$$s^{2}+2s+1-j_{3}^{2}$$