Solve (r)=27-1/4+5x+3

$$( r ) = \frac { 27 - 1 } { 4 + 5 x } + 3$$

Solve for x

$$x=-\frac{2\left(19-2r\right)}{5\left(3-r\right)}$$

$$r\neq 3$$

Steps for Solving Linear Equation

Variable x cannot be equal to -\frac{4}{5} since division by zero is not defined. Multiply both sides of the equation by 5x+4.

$$r\left(5x+4\right)=27-1+\left(5x+4\right)\times 3$$

Use the distributive property to multiply r by 5x+4.

$$5rx+4r=27-1+\left(5x+4\right)\times 3$$

Subtract 1 from 27 to get 26.

$$5rx+4r=26+\left(5x+4\right)\times 3$$

Use the distributive property to multiply 5x+4 by 3.

$$5rx+4r=26+15x+12$$

Add 26 and 12 to get 38.

$$5rx+4r=38+15x$$

Subtract 15x from both sides.

$$5rx+4r-15x=38$$

Subtract 4r from both sides.

$$5rx-15x=38-4r$$

Combine all terms containing x.

$$\left(5r-15\right)x=38-4r$$

Divide both sides by 5r-15.

$$\frac{\left(5r-15\right)x}{5r-15}=\frac{38-4r}{5r-15}$$

Dividing by 5r-15 undoes the multiplication by 5r-15.

$$x=\frac{38-4r}{5r-15}$$

Divide 38-4r by 5r-15.

$$x=\frac{2\left(19-2r\right)}{5\left(r-3\right)}$$

Variable x cannot be equal to -\frac{4}{5}.

$$x=\frac{2\left(19-2r\right)}{5\left(r-3\right)}\text{, }x\neq -\frac{4}{5}$$

Solve for r

$$r=\frac{15x+38}{5x+4}$$

$$x\neq -\frac{4}{5}$$