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Solve for r
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r+3=\sqrt{17} r+3=-\sqrt{17}
Take the square root of both sides of the equation.
r+3-3=\sqrt{17}-3 r+3-3=-\sqrt{17}-3
Subtract 3 from both sides of the equation.
r=\sqrt{17}-3 r=-\sqrt{17}-3
Subtracting 3 from itself leaves 0.