Solve (n^2+2n+4)

$$( n ^ { 2 } + 2 n + 4 )$$

Differentiate w.r.t. n

$$2\left(n+1\right)$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2n^{2-1}+2n^{1-1}$$

Subtract 1 from 2.

$$2n^{1}+2n^{1-1}$$

Subtract 1 from 1.

$$2n^{1}+2n^{0}$$

For any term t, t^{1}=t.

$$2n+2n^{0}$$

For any term t except 0, t^{0}=1.

$$2n+2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2n+2$$

Evaluate

$$n^{2}+2n+4$$