Solve (k-5)x+6=1-5

$$( k - 5 ) x + 6 = 1 - 5$$

Solve for k

$$k=5-\frac{10}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply k-5 by x.

$$kx-5x+6=1-5$$

Subtract 5 from 1 to get -4.

$$kx-5x+6=-4$$

Add 5x to both sides.

$$kx+6=-4+5x$$

Subtract 6 from both sides.

$$kx=-4+5x-6$$

Subtract 6 from -4 to get -10.

$$kx=-10+5x$$

The equation is in standard form.

$$xk=5x-10$$

Divide both sides by x.

$$\frac{xk}{x}=\frac{5x-10}{x}$$

Dividing by x undoes the multiplication by x.

$$k=\frac{5x-10}{x}$$

Divide -10+5x by x.

$$k=5-\frac{10}{x}$$

Solve for x

$$x=-\frac{10}{k-5}$$

$$k\neq 5$$

Steps for Solving Linear Equation

Use the distributive property to multiply k-5 by x.

$$kx-5x+6=1-5$$

Subtract 5 from 1 to get -4.

$$kx-5x+6=-4$$

Subtract 6 from both sides.

$$kx-5x=-4-6$$

Subtract 6 from -4 to get -10.

$$kx-5x=-10$$

Combine all terms containing x.

$$\left(k-5\right)x=-10$$

Divide both sides by k-5.

$$\frac{\left(k-5\right)x}{k-5}=-\frac{10}{k-5}$$

Dividing by k-5 undoes the multiplication by k-5.

$$x=-\frac{10}{k-5}$$