Solve (k^2+9)^2=

$$( k ^ { 2 } + 9 ) ^ { 2 } =$$

Evaluate

$$\left(k^{2}+9\right)^{2}$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(k^{2}+9\right)^{2}.

$$\left(k^{2}\right)^{2}+18k^{2}+81$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$k^{4}+18k^{2}+81$$

Expand

$$k^{4}+18k^{2}+81$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(k^{2}+9\right)^{2}.

$$\left(k^{2}\right)^{2}+18k^{2}+81$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$k^{4}+18k^{2}+81$$