Solve (k+4)^2-16=16

$$( k + 4 ) ^ { 2 } - 16 = 16$$

Solve for k

$$k=4\sqrt{2}-4\approx 1.656854249$$

$$k=-4\sqrt{2}-4\approx -9.656854249$$

Steps by Finding Square Root

Add 16 to both sides of the equation.

$$\left(k+4\right)^{2}-16+16=16+16$$

Subtracting 16 from itself leaves 0.

$$\left(k+4\right)^{2}=16+16$$

Add 16 to 16.

$$\left(k+4\right)^{2}=32$$

Take the square root of both sides of the equation.

$$k+4=4\sqrt{2} k+4=-4\sqrt{2}$$

Subtract 4 from both sides of the equation.

$$k+4-4=4\sqrt{2}-4 k+4-4=-4\sqrt{2}-4$$

Subtracting 4 from itself leaves 0.

$$k=4\sqrt{2}-4 k=-4\sqrt{2}-4$$