Solve (f24^x+1+2^x+3=320gi

$$( f 24 ^ { x + 1 } + 2 ^ { x + 3 } = 320 g i$$

Solve for f

$$f=-\frac{2^{x}-40ig}{3\times 24^{x}}$$

Steps for Solving Linear Equation

Multiply 320 and i to get 320i.

$$f\times 24^{x+1}+2^{x+3}=320ig$$

Subtract 2^{x+3} from both sides.

$$f\times 24^{x+1}=320ig-2^{x+3}$$

The equation is in standard form.

$$24^{x+1}f=320ig-2^{x+3}$$

Divide both sides by 24^{x+1}.

$$\frac{24^{x+1}f}{24^{x+1}}=\frac{320ig-8\times 2^{x}}{24^{x+1}}$$

Dividing by 24^{x+1} undoes the multiplication by 24^{x+1}.

$$f=\frac{320ig-8\times 2^{x}}{24^{x+1}}$$

Divide 320ig-8\times 2^{x} by 24^{x+1}.

$$f=\frac{40ig-2^{x}}{3\times 24^{x}}$$

Solve for g

$$g=\frac{-3if\times 24^{x}-i\times 2^{x}}{40}$$

Steps for Solving Linear Equation

Multiply 320 and i to get 320i.

$$f\times 24^{x+1}+2^{x+3}=320ig$$

Swap sides so that all variable terms are on the left hand side.

$$320ig=f\times 24^{x+1}+2^{x+3}$$

Divide both sides by 320i.

$$\frac{320ig}{320i}=\frac{24f\times 24^{x}+8\times 2^{x}}{320i}$$

Dividing by 320i undoes the multiplication by 320i.

$$g=\frac{24f\times 24^{x}+8\times 2^{x}}{320i}$$

Divide 24\times 24^{x}f+8\times 2^{x} by 320i.

$$g=\frac{-3if\times 24^{x}-i\times 2^{x}}{40}$$