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c^{2}+24c+144=144
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(c+12\right)^{2}.
c^{2}+24c+144-144=0
Subtract 144 from both sides.
c^{2}+24c=0
Subtract 144 from 144 to get 0.
c\left(c+24\right)=0
Factor out c.
c=0 c=-24
To find equation solutions, solve c=0 and c+24=0.
c^{2}+24c+144=144
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(c+12\right)^{2}.
c^{2}+24c+144-144=0
Subtract 144 from both sides.
c^{2}+24c=0
Subtract 144 from 144 to get 0.
c=\frac{-24±\sqrt{24^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 24 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
c=\frac{-24±24}{2}
Take the square root of 24^{2}.
c=\frac{0}{2}
Now solve the equation c=\frac{-24±24}{2} when ± is plus. Add -24 to 24.
c=0
Divide 0 by 2.
c=-\frac{48}{2}
Now solve the equation c=\frac{-24±24}{2} when ± is minus. Subtract 24 from -24.
c=-24
Divide -48 by 2.
c=0 c=-24
The equation is now solved.
\sqrt{\left(c+12\right)^{2}}=\sqrt{144}
Take the square root of both sides of the equation.
c+12=12 c+12=-12
Simplify.
c=0 c=-24
Subtract 12 from both sides of the equation.