Solve (b^2+8)(b^2-8)

$$( b ^ { 2 } + 8 ) ( b ^ { 2 } - 8 )$$

Evaluate

$$b^{4}-64$$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 8.

$$\left(b^{2}\right)^{2}-64$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$b^{4}-64$$

Expand

$$b^{4}-64$$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 8.

$$\left(b^{2}\right)^{2}-64$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$b^{4}-64$$