Solve (ax+28y=-7

$$( a x + 28 y = - 7$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=-\frac{7\left(4y+1\right)}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=-\frac{1}{4}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 28y from both sides.

$$ax=-7-28y$$

The equation is in standard form.

$$xa=-28y-7$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{-28y-7}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{-28y-7}{x}$$

Divide -7-28y by x.

$$a=-\frac{7\left(4y+1\right)}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{7\left(4y+1\right)}{a}\text{, }&a\neq 0\\x\in \mathrm{C}\text{, }&y=-\frac{1}{4}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 28y from both sides.

$$ax=-7-28y$$

The equation is in standard form.

$$ax=-28y-7$$

Divide both sides by a.

$$\frac{ax}{a}=\frac{-28y-7}{a}$$

Dividing by a undoes the multiplication by a.

$$x=\frac{-28y-7}{a}$$

Divide -7-28y by a.

$$x=-\frac{7\left(4y+1\right)}{a}$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{7\left(4y+1\right)}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=-\frac{1}{4}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 28y from both sides.

$$ax=-7-28y$$

The equation is in standard form.

$$xa=-28y-7$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{-28y-7}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{-28y-7}{x}$$

Divide -7-28y by x.

$$a=-\frac{7\left(4y+1\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{7\left(4y+1\right)}{a}\text{, }&a\neq 0\\x\in \mathrm{R}\text{, }&y=-\frac{1}{4}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 28y from both sides.

$$ax=-7-28y$$

The equation is in standard form.

$$ax=-28y-7$$

Divide both sides by a.

$$\frac{ax}{a}=\frac{-28y-7}{a}$$

Dividing by a undoes the multiplication by a.

$$x=\frac{-28y-7}{a}$$

Divide -7-28y by a.

$$x=-\frac{7\left(4y+1\right)}{a}$$