Solve (a-b)^2+6(2a+b)

$$( a - b ) ^ { 2 } + 6 ( 2 a + b )$$

Evaluate

$$\left(a-b\right)^{2}+6b+12a$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-b\right)^{2}.

$$a^{2}-2ab+b^{2}+6\left(2a+b\right)$$

Use the distributive property to multiply 6 by 2a+b.

$$a^{2}-2ab+b^{2}+12a+6b$$

Expand

$$a^{2}-2ab+12a+b^{2}+6b$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-b\right)^{2}.

$$a^{2}-2ab+b^{2}+6\left(2a+b\right)$$

Use the distributive property to multiply 6 by 2a+b.

$$a^{2}-2ab+b^{2}+12a+6b$$