Solve (a-3b)^2-2a+bb^2

$$( a - 3 b ) ^ { 2 } - 2 a + b b ^ { 2 }$$

Evaluate

$$b^{3}+\left(a-3b\right)^{2}-2a$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\left(a-3b\right)^{2}-2a+b^{3}$$

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-3b\right)^{2}.

$$a^{2}-6ab+9b^{2}-2a+b^{3}$$

Expand

$$a^{2}-6ab-2a+b^{3}+9b^{2}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\left(a-3b\right)^{2}-2a+b^{3}$$

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(a-3b\right)^{2}.

$$a^{2}-6ab+9b^{2}-2a+b^{3}$$