Solve for a (complex solution)
\left\{\begin{matrix}a=-\frac{1-3x}{y}\text{, }&y\neq 0\\a\in \mathrm{C}\text{, }&x=\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=-\frac{1-3x}{y}\text{, }&y\neq 0\\a\in \mathrm{R}\text{, }&x=\frac{1}{3}\text{ and }y=0\end{matrix}\right.
Solve for x
x=\frac{ay+1}{3}
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ya=3x-1
The equation is in standard form.
\frac{ya}{y}=\frac{3x-1}{y}
Divide both sides by y.
a=\frac{3x-1}{y}
Dividing by y undoes the multiplication by y.
ya=3x-1
The equation is in standard form.
\frac{ya}{y}=\frac{3x-1}{y}
Divide both sides by y.
a=\frac{3x-1}{y}
Dividing by y undoes the multiplication by y.
3x-1=ay
Swap sides so that all variable terms are on the left hand side.
3x=ay+1
Add 1 to both sides.
\frac{3x}{3}=\frac{ay+1}{3}
Divide both sides by 3.
x=\frac{ay+1}{3}
Dividing by 3 undoes the multiplication by 3.
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