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a^{3}+3a^{2}+3a+1+7a+19
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(a+1\right)^{3}.
a^{3}+3a^{2}+10a+1+19
Combine 3a and 7a to get 10a.
a^{3}+3a^{2}+10a+20
Add 1 and 19 to get 20.
a^{3}+3a^{2}+3a+1+7a+19
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(a+1\right)^{3}.
a^{3}+3a^{2}+10a+1+19
Combine 3a and 7a to get 10a.
a^{3}+3a^{2}+10a+20
Add 1 and 19 to get 20.