Solve (I)x+3y=-18

$$( I ) x + 3 y = - 18$$

Solve for I (complex solution)

$$\left\{\begin{matrix}I=-\frac{3\left(y+6\right)}{x}\text{, }&x\neq 0\\I\in \mathrm{C}\text{, }&y=-6\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides.

$$Ix=-18-3y$$

The equation is in standard form.

$$xI=-3y-18$$

Divide both sides by x.

$$\frac{xI}{x}=\frac{-3y-18}{x}$$

Dividing by x undoes the multiplication by x.

$$I=\frac{-3y-18}{x}$$

Divide -18-3y by x.

$$I=-\frac{3\left(y+6\right)}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{3\left(y+6\right)}{I}\text{, }&I\neq 0\\x\in \mathrm{C}\text{, }&y=-6\text{ and }I=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides.

$$Ix=-18-3y$$

The equation is in standard form.

$$Ix=-3y-18$$

Divide both sides by I.

$$\frac{Ix}{I}=\frac{-3y-18}{I}$$

Dividing by I undoes the multiplication by I.

$$x=\frac{-3y-18}{I}$$

Divide -18-3y by I.

$$x=-\frac{3\left(y+6\right)}{I}$$

Solve for I

$$\left\{\begin{matrix}I=-\frac{3\left(y+6\right)}{x}\text{, }&x\neq 0\\I\in \mathrm{R}\text{, }&y=-6\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides.

$$Ix=-18-3y$$

The equation is in standard form.

$$xI=-3y-18$$

Divide both sides by x.

$$\frac{xI}{x}=\frac{-3y-18}{x}$$

Dividing by x undoes the multiplication by x.

$$I=\frac{-3y-18}{x}$$

Divide -18-3y by x.

$$I=-\frac{3\left(y+6\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{3\left(y+6\right)}{I}\text{, }&I\neq 0\\x\in \mathrm{R}\text{, }&y=-6\text{ and }I=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides.

$$Ix=-18-3y$$

The equation is in standard form.

$$Ix=-3y-18$$

Divide both sides by I.

$$\frac{Ix}{I}=\frac{-3y-18}{I}$$

Dividing by I undoes the multiplication by I.

$$x=\frac{-3y-18}{I}$$

Divide -18-3y by I.

$$x=-\frac{3\left(y+6\right)}{I}$$