Solve (8y+2)+(-10y-2)=

$$( 8 y + 2 ) + ( - 10 y - 2 ) =$$

Evaluate

$$-2y$$

Solution Steps

Combine 8y and -10y to get -2y.

$$-2y+2-2$$

Subtract 2 from 2 to get 0.

$$-2y$$

Differentiate w.r.t. y

$$-2$$

Steps Using Definition of a Derivative

Combine 8y and -10y to get -2y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-2y+2-2)$$

Subtract 2 from 2 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-2y)$$

The derivative of ax^{n} is nax^{n-1}.

$$-2y^{1-1}$$

Subtract 1 from 1.

$$-2y^{0}$$

For any term t except 0, t^{0}=1.

$$-2$$