Solve (8xy^2)*(-2x^3y)

$$( 8 x y ^ { 2 } ) \cdot ( - 2 x ^ { 3 } y )$$

Evaluate

$$-16y^{3}x^{4}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$8^{1}x^{1}y^{2}\left(-2\right)^{1}x^{3}y^{1}$$

Use the Commutative Property of Multiplication.

$$8^{1}\left(-2\right)^{1}x^{1}x^{3}y^{2}y^{1}$$

To multiply powers of the same base, add their exponents.

$$8^{1}\left(-2\right)^{1}x^{1+3}y^{2+1}$$

Add the exponents 1 and 3.

$$8^{1}\left(-2\right)^{1}x^{4}y^{2+1}$$

Add the exponents 2 and 1.

$$8^{1}\left(-2\right)^{1}x^{4}y^{3}$$

Multiply 8 times -2.

$$-16x^{4}y^{3}$$

Differentiate w.r.t. x

$$-64\left(xy\right)^{3}$$