Solve (8)-120*(-38/9)+(-7)*(-38/9)+37*(-38/9)

$$( 8 ) - 120 \times ( - 3 \frac { 8 } { 9 } ) + ( - 7 ) \times ( - 3 \frac { 8 } { 9 } ) + 37 \times ( - 3 \frac { 8 } { 9 } )$$

Evaluate

$$358$$

Solution Steps

Multiply 3 and 9 to get 27.

$$8-120\left(-\frac{27+8}{9}\right)-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Add 27 and 8 to get 35.

$$8-120\left(-\frac{35}{9}\right)-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Express 120\left(-\frac{35}{9}\right) as a single fraction.

$$8-\frac{120\left(-35\right)}{9}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Multiply 120 and -35 to get -4200.

$$8-\frac{-4200}{9}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Reduce the fraction \frac{-4200}{9} to lowest terms by extracting and canceling out 3.

$$8-\left(-\frac{1400}{3}\right)-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

The opposite of -\frac{1400}{3} is \frac{1400}{3}.

$$8+\frac{1400}{3}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{24}{3}+\frac{1400}{3}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Since \frac{24}{3} and \frac{1400}{3} have the same denominator, add them by adding their numerators.

$$\frac{24+1400}{3}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Add 24 and 1400 to get 1424.

$$\frac{1424}{3}-7\left(-\frac{3\times 9+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Multiply 3 and 9 to get 27.

$$\frac{1424}{3}-7\left(-\frac{27+8}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Add 27 and 8 to get 35.

$$\frac{1424}{3}-7\left(-\frac{35}{9}\right)+37\left(-\frac{3\times 9+8}{9}\right)$$

Express -7\left(-\frac{35}{9}\right) as a single fraction.

$$\frac{1424}{3}+\frac{-7\left(-35\right)}{9}+37\left(-\frac{3\times 9+8}{9}\right)$$

Multiply -7 and -35 to get 245.

$$\frac{1424}{3}+\frac{245}{9}+37\left(-\frac{3\times 9+8}{9}\right)$$

Least common multiple of 3 and 9 is 9. Convert \frac{1424}{3} and \frac{245}{9} to fractions with denominator 9.

$$\frac{4272}{9}+\frac{245}{9}+37\left(-\frac{3\times 9+8}{9}\right)$$

Since \frac{4272}{9} and \frac{245}{9} have the same denominator, add them by adding their numerators.

$$\frac{4272+245}{9}+37\left(-\frac{3\times 9+8}{9}\right)$$

Add 4272 and 245 to get 4517.

$$\frac{4517}{9}+37\left(-\frac{3\times 9+8}{9}\right)$$

Multiply 3 and 9 to get 27.

$$\frac{4517}{9}+37\left(-\frac{27+8}{9}\right)$$

Add 27 and 8 to get 35.

$$\frac{4517}{9}+37\left(-\frac{35}{9}\right)$$

Express 37\left(-\frac{35}{9}\right) as a single fraction.

$$\frac{4517}{9}+\frac{37\left(-35\right)}{9}$$

Multiply 37 and -35 to get -1295.

$$\frac{4517}{9}+\frac{-1295}{9}$$

Fraction \frac{-1295}{9} can be rewritten as -\frac{1295}{9} by extracting the negative sign.

$$\frac{4517}{9}-\frac{1295}{9}$$

Since \frac{4517}{9} and \frac{1295}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4517-1295}{9}$$

Subtract 1295 from 4517 to get 3222.

$$\frac{3222}{9}$$

Divide 3222 by 9 to get 358.

$$358$$

Factor

$$2\times 179$$