Solve (8/9+3/15)-6/45

$$( 8 / 9 + 3 / 15 ) - 6 / 45$$

Evaluate

$$\frac{43}{45}\approx 0.955555556$$

Solution Steps

Reduce the fraction \frac{3}{15} to lowest terms by extracting and canceling out 3.

$$\frac{8}{9}+\frac{1}{5}-\frac{6}{45}$$

Least common multiple of 9 and 5 is 45. Convert \frac{8}{9} and \frac{1}{5} to fractions with denominator 45.

$$\frac{40}{45}+\frac{9}{45}-\frac{6}{45}$$

Since \frac{40}{45} and \frac{9}{45} have the same denominator, add them by adding their numerators.

$$\frac{40+9}{45}-\frac{6}{45}$$

Add 40 and 9 to get 49.

$$\frac{49}{45}-\frac{6}{45}$$

Since \frac{49}{45} and \frac{6}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-6}{45}$$

Subtract 6 from 49 to get 43.

$$\frac{43}{45}$$

Factor

$$\frac{43}{3 ^ {2} \cdot 5} = 0.9555555555555556$$