Evaluate
\text{Indeterminate}
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64+16\sqrt{-2}+\left(\sqrt{-2}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(8+\sqrt{-2}\right)^{2}.
64+16\sqrt{-2}-2
Calculate \sqrt{-2} to the power of 2 and get -2.
62+16\sqrt{-2}
Subtract 2 from 64 to get 62.
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