Solve (7x-5xy-3y)=0

$$( 7 x - 5 x y - 3 y ) = 0$$

Solve for x

$$x=\frac{3y}{7-5y}$$

$$y\neq \frac{7}{5}$$

Steps for Solving Linear Equation

Add 3y to both sides. Anything plus zero gives itself.

$$7x-5xy=3y$$

Combine all terms containing x.

$$\left(7-5y\right)x=3y$$

Divide both sides by 7-5y.

$$\frac{\left(7-5y\right)x}{7-5y}=\frac{3y}{7-5y}$$

Dividing by 7-5y undoes the multiplication by 7-5y.

$$x=\frac{3y}{7-5y}$$

Solve for y

$$y=\frac{7x}{5x+3}$$

$$x\neq -\frac{3}{5}$$

Steps for Solving Linear Equation

Subtract 7x from both sides. Anything subtracted from zero gives its negation.

$$-5xy-3y=-7x$$

Combine all terms containing y.

$$\left(-5x-3\right)y=-7x$$

Divide both sides by -5x-3.

$$\frac{\left(-5x-3\right)y}{-5x-3}=-\frac{7x}{-5x-3}$$

Dividing by -5x-3 undoes the multiplication by -5x-3.

$$y=-\frac{7x}{-5x-3}$$

Divide -7x by -5x-3.

$$y=\frac{7x}{5x+3}$$