Solve (6a-b)^2+3(a-b)

$$( 6 a - b ) ^ { 2 } + 3 ( a - b )$$

Evaluate

$$\left(6a-b\right)^{2}+3a-3b$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(6a-b\right)^{2}.

$$36a^{2}-12ab+b^{2}+3\left(a-b\right)$$

Use the distributive property to multiply 3 by a-b.

$$36a^{2}-12ab+b^{2}+3a-3b$$

Expand

$$36a^{2}-12ab+3a+b^{2}-3b$$

Solution Steps

Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(6a-b\right)^{2}.

$$36a^{2}-12ab+b^{2}+3\left(a-b\right)$$

Use the distributive property to multiply 3 by a-b.

$$36a^{2}-12ab+b^{2}+3a-3b$$