Solve (6a-3)+(-4a+3)

$$( 6 a - 3 ) + ( - 4 a + 3 )$$

Evaluate

$$2a$$

Solution Steps

Combine 6a and -4a to get 2a.

$$2a-3+3$$

Add -3 and 3 to get 0.

$$2a$$

Differentiate w.r.t. a

$$2$$

Steps Using Definition of a Derivative

Combine 6a and -4a to get 2a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(2a-3+3)$$

Add -3 and 3 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}a}(2a)$$

The derivative of ax^{n} is nax^{n-1}.

$$2a^{1-1}$$

Subtract 1 from 1.

$$2a^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$