Solve (6-2x^7)^2

$$( 6 - 2 x ^ { 7 } ) ^ { 2 }$$

Evaluate

$$4\left(3-x^{7}\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6-2x^{7}\right)^{2}.

$$36-24x^{7}+4\left(x^{7}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 7 and 2 to get 14.

$$36-24x^{7}+4x^{14}$$

Expand

$$4x^{14}-24x^{7}+36$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6-2x^{7}\right)^{2}.

$$36-24x^{7}+4\left(x^{7}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 7 and 2 to get 14.

$$36-24x^{7}+4x^{14}$$