Solve (6-2i)(3i

$$( 6 - 2 i ) ( 3 i$$

Evaluate

$$6+18i$$

Solution Steps

Multiply 6-2i times 3i.

$$6\times \left(3i\right)-2\times 3i^{2}$$

By definition, i^{2} is -1.

$$6\times \left(3i\right)-2\times 3\left(-1\right)$$

Do the multiplications. Reorder the terms.

$$6+18i$$

Real Part

$$6$$

Solution Steps

Multiply 6-2i times 3i.

$$Re(6\times \left(3i\right)-2\times 3i^{2})$$

By definition, i^{2} is -1.

$$Re(6\times \left(3i\right)-2\times 3\left(-1\right))$$

Do the multiplications in 6\times \left(3i\right)-2\times 3\left(-1\right). Reorder the terms.

$$Re(6+18i)$$

The real part of 6+18i is 6.

$$6$$