Solve (6-5/6)*4/3-1/3=

$$( 6 - \frac { 5 } { 6 } ) \cdot \frac { 4 } { 3 } - \frac { 1 } { 3 } =$$

Evaluate

$$\frac{59}{9}\approx 6.555555556$$

Solution Steps

Convert 6 to fraction \frac{36}{6}.

$$\left(\frac{36}{6}-\frac{5}{6}\right)\times \frac{4}{3}-\frac{1}{3}$$

Since \frac{36}{6} and \frac{5}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-5}{6}\times \frac{4}{3}-\frac{1}{3}$$

Subtract 5 from 36 to get 31.

$$\frac{31}{6}\times \frac{4}{3}-\frac{1}{3}$$

Multiply \frac{31}{6} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{31\times 4}{6\times 3}-\frac{1}{3}$$

Do the multiplications in the fraction \frac{31\times 4}{6\times 3}.

$$\frac{124}{18}-\frac{1}{3}$$

Reduce the fraction \frac{124}{18} to lowest terms by extracting and canceling out 2.

$$\frac{62}{9}-\frac{1}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{62}{9} and \frac{1}{3} to fractions with denominator 9.

$$\frac{62}{9}-\frac{3}{9}$$

Since \frac{62}{9} and \frac{3}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{62-3}{9}$$

Subtract 3 from 62 to get 59.

$$\frac{59}{9}$$

Factor

$$\frac{59}{3 ^ {2}} = 6\frac{5}{9} = 6.555555555555555$$