Solve (6)+15+(28)+(3b-15)

$$( 6 ) + 15 + ( 28 ) + ( 3 b - 15 )$$

Evaluate

$$3b+34$$

Solution Steps

Add 6 and 15 to get 21.

$$21+28+3b-15$$

Add 21 and 28 to get 49.

$$49+3b-15$$

Subtract 15 from 49 to get 34.

$$34+3b$$

Differentiate w.r.t. b

$$3$$

Steps Using Derivative Rule for Sum

Add 6 and 15 to get 21.

$$\frac{\mathrm{d}}{\mathrm{d}b}(21+28+3b-15)$$

Add 21 and 28 to get 49.

$$\frac{\mathrm{d}}{\mathrm{d}b}(49+3b-15)$$

Subtract 15 from 49 to get 34.

$$\frac{\mathrm{d}}{\mathrm{d}b}(34+3b)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3b^{1-1}$$

Subtract 1 from 1.

$$3b^{0}$$

For any term t except 0, t^{0}=1.

$$3\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3$$