Solve (6*8+7*6+8*4+9*2)div(8+6+4+2)=

$$( 6 \times 8 + 7 \times 6 + 8 \times 4 + 9 \times 2 ) \div ( 8 + 6 + 4 + 2 ) =$$

Evaluate

$$7$$

Solution Steps

Multiply 6 and 8 to get 48. Multiply 7 and 6 to get 42. Multiply 8 and 4 to get 32. Multiply 9 and 2 to get 18.

$$\frac{48+42+32+18}{8+6+4+2}$$

Add 48 and 42 to get 90.

$$\frac{90+32+18}{8+6+4+2}$$

Add 90 and 32 to get 122.

$$\frac{122+18}{8+6+4+2}$$

Add 122 and 18 to get 140.

$$\frac{140}{8+6+4+2}$$

Add 8 and 6 to get 14.

$$\frac{140}{14+4+2}$$

Add 14 and 4 to get 18.

$$\frac{140}{18+2}$$

Add 18 and 2 to get 20.

$$\frac{140}{20}$$

Divide 140 by 20 to get 7.

$$7$$

Factor

$$7$$