Solve (6sqrt{3}-2/3sqrt{3}+4sqrt{3})div2sqrt{3}

$$( 6 \sqrt { 3 } - \frac { 2 } { 3 } \sqrt { 3 } + 4 \sqrt { 3 } ) \div 2 \sqrt { 3 }$$

Evaluate

$$14$$

Solution Steps

Combine 6\sqrt{3} and -\frac{2}{3}\sqrt{3} to get \frac{16}{3}\sqrt{3}.

$$\frac{\frac{16}{3}\sqrt{3}+4\sqrt{3}}{2}\sqrt{3}$$

Combine \frac{16}{3}\sqrt{3} and 4\sqrt{3} to get \frac{28}{3}\sqrt{3}.

$$\frac{\frac{28}{3}\sqrt{3}}{2}\sqrt{3}$$

Divide \frac{28}{3}\sqrt{3} by 2 to get \frac{14}{3}\sqrt{3}.

$$\frac{14}{3}\sqrt{3}\sqrt{3}$$

Multiply \sqrt{3} and \sqrt{3} to get 3.

$$\frac{14}{3}\times 3$$

Cancel out 3 and 3.

$$14$$

Factor

$$2\times 7$$