Solve (65/6+32/12):10=

$$( 6 \frac { 5 } { 6 } + 3 \frac { 2 } { 12 } ) : 10 =$$

Evaluate

$$1$$

Solution Steps

Multiply 6 and 6 to get 36.

$$\frac{\frac{36+5}{6}+\frac{3\times 12+2}{12}}{10}$$

Add 36 and 5 to get 41.

$$\frac{\frac{41}{6}+\frac{3\times 12+2}{12}}{10}$$

Multiply 3 and 12 to get 36.

$$\frac{\frac{41}{6}+\frac{36+2}{12}}{10}$$

Add 36 and 2 to get 38.

$$\frac{\frac{41}{6}+\frac{38}{12}}{10}$$

Reduce the fraction \frac{38}{12} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{41}{6}+\frac{19}{6}}{10}$$

Since \frac{41}{6} and \frac{19}{6} have the same denominator, add them by adding their numerators.

$$\frac{\frac{41+19}{6}}{10}$$

Add 41 and 19 to get 60.

$$\frac{\frac{60}{6}}{10}$$

Divide 60 by 6 to get 10.

$$\frac{10}{10}$$

Divide 10 by 10 to get 1.

$$1$$

Factor

$$1$$