Solve (6+4-x)^2=(4+x^2)

$$( 6 + 4 - x ) ^ { 2 } = ( 4 + x ^ { 2 } )$$

Solve for x

$$x = \frac{24}{5} = 4\frac{4}{5} = 4.8$$

Steps for Solving Linear Equation

Add 6 and 4 to get 10.

$$\left(10-x\right)^{2}=4+x^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(10-x\right)^{2}.

$$100-20x+x^{2}=4+x^{2}$$

Subtract x^{2} from both sides.

$$100-20x+x^{2}-x^{2}=4$$

Combine x^{2} and -x^{2} to get 0.

$$100-20x=4$$

Subtract 100 from both sides.

$$-20x=4-100$$

Subtract 100 from 4 to get -96.

$$-20x=-96$$

Divide both sides by -20.

$$x=\frac{-96}{-20}$$

Reduce the fraction \frac{-96}{-20} to lowest terms by extracting and canceling out -4.

$$x=\frac{24}{5}$$