Solve (6+2)*(7-4)div(14-2)+(12-8)*(7+3)div(10-2)

$$( 6 + 2 ) \times ( 7 - 4 ) \div ( 14 - 2 ) + ( 12 - 8 ) \times ( 7 + 3 ) \div ( 10 - 2 )$$

Evaluate

$$7$$

Solution Steps

Add 6 and 2 to get 8.

$$\frac{8\left(7-4\right)}{14-2}+\frac{\left(12-8\right)\left(7+3\right)}{10-2}$$

Subtract 4 from 7 to get 3.

$$\frac{8\times 3}{14-2}+\frac{\left(12-8\right)\left(7+3\right)}{10-2}$$

Multiply 8 and 3 to get 24.

$$\frac{24}{14-2}+\frac{\left(12-8\right)\left(7+3\right)}{10-2}$$

Subtract 2 from 14 to get 12.

$$\frac{24}{12}+\frac{\left(12-8\right)\left(7+3\right)}{10-2}$$

Divide 24 by 12 to get 2.

$$2+\frac{\left(12-8\right)\left(7+3\right)}{10-2}$$

Subtract 8 from 12 to get 4.

$$2+\frac{4\left(7+3\right)}{10-2}$$

Add 7 and 3 to get 10.

$$2+\frac{4\times 10}{10-2}$$

Multiply 4 and 10 to get 40.

$$2+\frac{40}{10-2}$$

Subtract 2 from 10 to get 8.

$$2+\frac{40}{8}$$

Divide 40 by 8 to get 5.

$$2+5$$

Add 2 and 5 to get 7.

$$7$$

Factor

$$7$$