Solve (5t_{6}+3+a+b-a)+20=305

$$( 5 t _ { 6 } + 3 + a + b - a ) + 20 = 305$$

Solve for b

$$b=282-5t_{6}$$

Solution Steps

Combine a and -a to get 0.

$$5t_{6}+3+b+20=305$$

Add 3 and 20 to get 23.

$$5t_{6}+23+b=305$$

Subtract 5t_{6} from both sides.

$$23+b=305-5t_{6}$$

Subtract 23 from both sides.

$$b=305-5t_{6}-23$$

Subtract 23 from 305 to get 282.

$$b=282-5t_{6}$$

Solve for a (complex solution)

$$a\in \mathrm{C}$$

$$t_{6}=\frac{282-b}{5}$$

Solve for a

$$a\in \mathrm{R}$$

$$t_{6}=\frac{282-b}{5}$$