Solve (5c+2/3)^2=0

$$( 5 c + \frac { 2 } { 3 } ) ^ { 2 } = 0$$

Solve for c

$$c=-\frac{2}{15}\approx -0.133333333$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$5c+\frac{2}{3}=0 5c+\frac{2}{3}=0$$

Subtract \frac{2}{3} from both sides of the equation.

$$5c+\frac{2}{3}-\frac{2}{3}=-\frac{2}{3} 5c+\frac{2}{3}-\frac{2}{3}=-\frac{2}{3}$$

Subtracting \frac{2}{3} from itself leaves 0.

$$5c=-\frac{2}{3} 5c=-\frac{2}{3}$$

Subtract \frac{2}{3} from 0.

$$5c=-\frac{2}{3}$$

Divide both sides by 5.

$$\frac{5c}{5}=-\frac{\frac{2}{3}}{5} \frac{5c}{5}=-\frac{\frac{2}{3}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$c=-\frac{\frac{2}{3}}{5} c=-\frac{\frac{2}{3}}{5}$$

Divide -\frac{2}{3} by 5.

$$c=-\frac{2}{15}$$