Solve (5-4+2-1)+(2/3-1/6+3/4-1/4)

$$( 5 - 4 + 2 - 1 ) + ( \frac { 2 } { 3 } - \frac { 1 } { 6 } + \frac { 3 } { 4 } - \frac { 1 } { 4 } )$$

Evaluate

$$3$$

Solution Steps

Subtract 4 from 5 to get 1.

$$1+2-1+\frac{2}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Add 1 and 2 to get 3.

$$3-1+\frac{2}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Subtract 1 from 3 to get 2.

$$2+\frac{2}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}+\frac{2}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{6+2}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Add 6 and 2 to get 8.

$$\frac{8}{3}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Least common multiple of 3 and 6 is 6. Convert \frac{8}{3} and \frac{1}{6} to fractions with denominator 6.

$$\frac{16}{6}-\frac{1}{6}+\frac{3}{4}-\frac{1}{4}$$

Since \frac{16}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-1}{6}+\frac{3}{4}-\frac{1}{4}$$

Subtract 1 from 16 to get 15.

$$\frac{15}{6}+\frac{3}{4}-\frac{1}{4}$$

Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.

$$\frac{5}{2}+\frac{3}{4}-\frac{1}{4}$$

Least common multiple of 2 and 4 is 4. Convert \frac{5}{2} and \frac{3}{4} to fractions with denominator 4.

$$\frac{10}{4}+\frac{3}{4}-\frac{1}{4}$$

Since \frac{10}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{10+3}{4}-\frac{1}{4}$$

Add 10 and 3 to get 13.

$$\frac{13}{4}-\frac{1}{4}$$

Since \frac{13}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-1}{4}$$

Subtract 1 from 13 to get 12.

$$\frac{12}{4}$$

Divide 12 by 4 to get 3.

$$3$$

Factor

$$3$$