Solve (5-2i)-2(3+i)

$$( 5 - 2 i ) - 2 ( 3 + i )$$

Evaluate

$$-1-4i$$

Solution Steps

Multiply 2 times 3+i.

$$5-2i-\left(2\times 3+2i\right)$$

Do the multiplications in 2\times 3+2i.

$$5-2i-\left(6+2i\right)$$

Subtract 6+2i from 5-2i by subtracting corresponding real and imaginary parts.

$$5-6+\left(-2-2\right)i$$

Subtract 6 from 5. Subtract 2 from -2.

$$-1-4i$$

Real Part

$$-1$$

Solution Steps

Multiply 2 times 3+i.

$$Re(5-2i-\left(2\times 3+2i\right))$$

Do the multiplications in 2\times 3+2i.

$$Re(5-2i-\left(6+2i\right))$$

Subtract 6+2i from 5-2i by subtracting corresponding real and imaginary parts.

$$Re(5-6+\left(-2-2\right)i)$$

Subtract 6 from 5. Subtract 2 from -2.

$$Re(-1-4i)$$

The real part of -1-4i is -1.

$$-1$$