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10\left(\sqrt{3}\right)^{2}-5\sqrt{3}+6\sqrt{3}-3
Apply the distributive property by multiplying each term of 5\sqrt{3}+3 by each term of 2\sqrt{3}-1.
10\times 3-5\sqrt{3}+6\sqrt{3}-3
The square of \sqrt{3} is 3.
30-5\sqrt{3}+6\sqrt{3}-3
Multiply 10 and 3 to get 30.
30+\sqrt{3}-3
Combine -5\sqrt{3} and 6\sqrt{3} to get \sqrt{3}.
27+\sqrt{3}
Subtract 3 from 30 to get 27.