Solve (5*2^2-3*2-2)+(-7*2^2+2*2-2)=

$$( 5 \cdot 2 ^ { 2 } - 3 \cdot 2 - 2 ) + ( - 7 \cdot 2 ^ { 2 } + 2 \cdot 2 - 2 ) =$$

Evaluate

$$-14$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$5\times 4-3\times 2-2-7\times 2^{2}+2\times 2-2$$

Multiply 5 and 4 to get 20.

$$20-3\times 2-2-7\times 2^{2}+2\times 2-2$$

Multiply 3 and 2 to get 6.

$$20-6-2-7\times 2^{2}+2\times 2-2$$

Subtract 6 from 20 to get 14.

$$14-2-7\times 2^{2}+2\times 2-2$$

Subtract 2 from 14 to get 12.

$$12-7\times 2^{2}+2\times 2-2$$

Calculate 2 to the power of 2 and get 4.

$$12-7\times 4+2\times 2-2$$

Multiply -7 and 4 to get -28.

$$12-28+2\times 2-2$$

Subtract 28 from 12 to get -16.

$$-16+2\times 2-2$$

Multiply 2 and 2 to get 4.

$$-16+4-2$$

Add -16 and 4 to get -12.

$$-12-2$$

Subtract 2 from -12 to get -14.

$$-14$$

Factor

$$-14$$