Solve (5^-5)^-1*(1/2)^-2*10^-5

$$( 5 ^ { - 5 } ) ^ { - 1 } \cdot ( \frac { 1 } { 2 } ) ^ { - 2 } \cdot 10 ^ { - 5 }$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -5 and -1 to get 5.

$$5^{5}\times \left(\frac{1}{2}\right)^{-2}\times 10^{-5}$$

Calculate 5 to the power of 5 and get 3125.

$$3125\times \left(\frac{1}{2}\right)^{-2}\times 10^{-5}$$

Calculate \frac{1}{2} to the power of -2 and get 4.

$$3125\times 4\times 10^{-5}$$

Multiply 3125 and 4 to get 12500.

$$12500\times 10^{-5}$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$12500\times \frac{1}{100000}$$

Multiply 12500 and \frac{1}{100000} to get \frac{1}{8}.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$