Solve (45%text{of}240)text{of}10+29^2-52%text{of}1350=?

$$( 45 \% \text { of } 240 ) \text { of } 10 + 29 ^ { 2 } - 52 \% \text { of } 1350 = ?$$

Evaluate

$$1219$$

Solution Steps

Reduce the fraction \frac{45}{100} to lowest terms by extracting and canceling out 5.

$$\frac{9}{20}\times 240\times 10+29^{2}-\frac{52}{100}\times 1350$$

Express \frac{9}{20}\times 240 as a single fraction.

$$\frac{9\times 240}{20}\times 10+29^{2}-\frac{52}{100}\times 1350$$

Multiply 9 and 240 to get 2160.

$$\frac{2160}{20}\times 10+29^{2}-\frac{52}{100}\times 1350$$

Divide 2160 by 20 to get 108.

$$108\times 10+29^{2}-\frac{52}{100}\times 1350$$

Multiply 108 and 10 to get 1080.

$$1080+29^{2}-\frac{52}{100}\times 1350$$

Calculate 29 to the power of 2 and get 841.

$$1080+841-\frac{52}{100}\times 1350$$

Add 1080 and 841 to get 1921.

$$1921-\frac{52}{100}\times 1350$$

Reduce the fraction \frac{52}{100} to lowest terms by extracting and canceling out 4.

$$1921-\frac{13}{25}\times 1350$$

Express \frac{13}{25}\times 1350 as a single fraction.

$$1921-\frac{13\times 1350}{25}$$

Multiply 13 and 1350 to get 17550.

$$1921-\frac{17550}{25}$$

Divide 17550 by 25 to get 702.

$$1921-702$$

Subtract 702 from 1921 to get 1219.

$$1219$$

Factor

$$23\times 53$$