Solve (4t-2)+(3t+7)

$$( 4 t - 2 ) + ( 3 t + 7 )$$

Evaluate

$$7t+5$$

Solution Steps

Combine 4t and 3t to get 7t.

$$7t-2+7$$

Add -2 and 7 to get 5.

$$7t+5$$

Differentiate w.r.t. t

$$7$$

Steps Using Derivative Rule for Sum

Combine 4t and 3t to get 7t.

$$\frac{\mathrm{d}}{\mathrm{d}t}(7t-2+7)$$

Add -2 and 7 to get 5.

$$\frac{\mathrm{d}}{\mathrm{d}t}(7t+5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$7t^{1-1}$$

Subtract 1 from 1.

$$7t^{0}$$

For any term t except 0, t^{0}=1.

$$7\times 1$$

For any term t, t\times 1=t and 1t=t.

$$7$$