Solve (4-2)^-5:(3+2)^-2

$$( 4 - 2 ) ^ { - 5 } : ( 3 + 2 ) ^ { - 2 }$$

Evaluate

$$\frac{25}{32}=0.78125$$

Solution Steps

Subtract 2 from 4 to get 2.

$$\frac{2^{-5}}{\left(3+2\right)^{-2}}$$

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$\frac{\frac{1}{32}}{\left(3+2\right)^{-2}}$$

Add 3 and 2 to get 5.

$$\frac{\frac{1}{32}}{5^{-2}}$$

Calculate 5 to the power of -2 and get \frac{1}{25}.

$$\frac{\frac{1}{32}}{\frac{1}{25}}$$

Divide \frac{1}{32} by \frac{1}{25} by multiplying \frac{1}{32} by the reciprocal of \frac{1}{25}.

$$\frac{1}{32}\times 25$$

Multiply \frac{1}{32} and 25 to get \frac{25}{32}.

$$\frac{25}{32}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {5}} = 0.78125$$