Solve (4-1/n)+(4-2/n)+(4-3/n)

$$( 4 - \frac { 1 } { n } ) + ( 4 - \frac { 2 } { n } ) + ( 4 - \frac { 3 } { n } )$$

Evaluate

$$12-\frac{6}{n}$$

Short Solution Steps

Add 4 and 4 to get 8.

$$8-\frac{1}{n}-\frac{2}{n}+4-\frac{3}{n}$$

Add 8 and 4 to get 12.

$$12-\frac{1}{n}-\frac{2}{n}-\frac{3}{n}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 12 times \frac{n}{n}.

$$\frac{12n}{n}-\frac{1}{n}-\frac{2}{n}-\frac{3}{n}$$

Since \frac{12n}{n} and \frac{1}{n} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12n-1}{n}-\frac{2}{n}-\frac{3}{n}$$

Since \frac{12n-1}{n} and \frac{2}{n} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12n-1-2}{n}-\frac{3}{n}$$

Combine like terms in 12n-1-2.

$$\frac{12n-3}{n}-\frac{3}{n}$$

Since \frac{12n-3}{n} and \frac{3}{n} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12n-3-3}{n}$$

Combine like terms in 12n-3-3.

$$\frac{12n-6}{n}$$

Factor

$$\frac{6\left(2n-1\right)}{n}$$