Solve (4*1/1*3*5*2/2*3+7*3/3*4)

$$( 4 * \frac { 1 } { 1 \cdot 3 } \cdot 5 \cdot \frac { 2 } { 2 \cdot 3 } + 7 \cdot \frac { 3 } { 3 \cdot 4 } )$$

Evaluate

$$\frac{143}{36}\approx 3.972222222$$

Solution Steps

Multiply 1 and 3 to get 3.

$$4\times \frac{1}{3}\times 5\times \frac{2}{2\times 3}+7\times \frac{3}{3\times 4}$$

Multiply 4 and \frac{1}{3} to get \frac{4}{3}.

$$\frac{4}{3}\times 5\times \frac{2}{2\times 3}+7\times \frac{3}{3\times 4}$$

Express \frac{4}{3}\times 5 as a single fraction.

$$\frac{4\times 5}{3}\times \frac{2}{2\times 3}+7\times \frac{3}{3\times 4}$$

Multiply 4 and 5 to get 20.

$$\frac{20}{3}\times \frac{2}{2\times 3}+7\times \frac{3}{3\times 4}$$

Multiply 2 and 3 to get 6.

$$\frac{20}{3}\times \frac{2}{6}+7\times \frac{3}{3\times 4}$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{20}{3}\times \frac{1}{3}+7\times \frac{3}{3\times 4}$$

Multiply \frac{20}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 1}{3\times 3}+7\times \frac{3}{3\times 4}$$

Do the multiplications in the fraction \frac{20\times 1}{3\times 3}.

$$\frac{20}{9}+7\times \frac{3}{3\times 4}$$

Multiply 3 and 4 to get 12.

$$\frac{20}{9}+7\times \frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{20}{9}+7\times \frac{1}{4}$$

Multiply 7 and \frac{1}{4} to get \frac{7}{4}.

$$\frac{20}{9}+\frac{7}{4}$$

Least common multiple of 9 and 4 is 36. Convert \frac{20}{9} and \frac{7}{4} to fractions with denominator 36.

$$\frac{80}{36}+\frac{63}{36}$$

Since \frac{80}{36} and \frac{63}{36} have the same denominator, add them by adding their numerators.

$$\frac{80+63}{36}$$

Add 80 and 63 to get 143.

$$\frac{143}{36}$$

Factor

$$\frac{11 \cdot 13}{2 ^ {2} \cdot 3 ^ {2}} = 3\frac{35}{36} = 3.9722222222222223$$