Solve (41/5)(-2/3)(9/12)(21/3)=

$$( 4 \frac { 1 } { 5 } ) ( - \frac { 2 } { 3 } ) ( \frac { 9 } { 12 } ) ( 2 \frac { 1 } { 3 } ) =$$

Evaluate

$$-\frac{49}{10}=-4.9$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\frac{20+1}{5}\left(-\frac{2}{3}\right)\times \frac{9}{12}\times \frac{2\times 3+1}{3}$$

Add 20 and 1 to get 21.

$$\frac{21}{5}\left(-\frac{2}{3}\right)\times \frac{9}{12}\times \frac{2\times 3+1}{3}$$

Multiply \frac{21}{5} times -\frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{21\left(-2\right)}{5\times 3}\times \frac{9}{12}\times \frac{2\times 3+1}{3}$$

Do the multiplications in the fraction \frac{21\left(-2\right)}{5\times 3}.

$$\frac{-42}{15}\times \frac{9}{12}\times \frac{2\times 3+1}{3}$$

Reduce the fraction \frac{-42}{15} to lowest terms by extracting and canceling out 3.

$$-\frac{14}{5}\times \frac{9}{12}\times \frac{2\times 3+1}{3}$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$-\frac{14}{5}\times \frac{3}{4}\times \frac{2\times 3+1}{3}$$

Multiply -\frac{14}{5} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-14\times 3}{5\times 4}\times \frac{2\times 3+1}{3}$$

Do the multiplications in the fraction \frac{-14\times 3}{5\times 4}.

$$\frac{-42}{20}\times \frac{2\times 3+1}{3}$$

Reduce the fraction \frac{-42}{20} to lowest terms by extracting and canceling out 2.

$$-\frac{21}{10}\times \frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$-\frac{21}{10}\times \frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$-\frac{21}{10}\times \frac{7}{3}$$

Multiply -\frac{21}{10} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-21\times 7}{10\times 3}$$

Do the multiplications in the fraction \frac{-21\times 7}{10\times 3}.

$$\frac{-147}{30}$$

Reduce the fraction \frac{-147}{30} to lowest terms by extracting and canceling out 3.

$$-\frac{49}{10}$$

Factor

$$-\frac{49}{10} = -4\frac{9}{10} = -4.9$$