Solve (4div7+1/6)*6-19/7

$$( 4 \div 7 + \frac { 1 } { 6 } ) \times 6 - \frac { 19 } { 7 }$$

Evaluate

$$\frac{12}{7}\approx 1.714285714$$

Solution Steps

Least common multiple of 7 and 6 is 42. Convert \frac{4}{7} and \frac{1}{6} to fractions with denominator 42.

$$\left(\frac{24}{42}+\frac{7}{42}\right)\times 6-\frac{19}{7}$$

Since \frac{24}{42} and \frac{7}{42} have the same denominator, add them by adding their numerators.

$$\frac{24+7}{42}\times 6-\frac{19}{7}$$

Add 24 and 7 to get 31.

$$\frac{31}{42}\times 6-\frac{19}{7}$$

Express \frac{31}{42}\times 6 as a single fraction.

$$\frac{31\times 6}{42}-\frac{19}{7}$$

Multiply 31 and 6 to get 186.

$$\frac{186}{42}-\frac{19}{7}$$

Reduce the fraction \frac{186}{42} to lowest terms by extracting and canceling out 6.

$$\frac{31}{7}-\frac{19}{7}$$

Since \frac{31}{7} and \frac{19}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{31-19}{7}$$

Subtract 19 from 31 to get 12.

$$\frac{12}{7}$$

Factor

$$\frac{2 ^ {2} \cdot 3}{7} = 1\frac{5}{7} = 1.7142857142857142$$