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\frac{\frac{4+12}{7}-\frac{9}{7}}{\frac{5}{4}-\frac{7}{3}}
Since \frac{4}{7} and \frac{12}{7} have the same denominator, add them by adding their numerators.
\frac{\frac{16}{7}-\frac{9}{7}}{\frac{5}{4}-\frac{7}{3}}
Add 4 and 12 to get 16.
\frac{\frac{16-9}{7}}{\frac{5}{4}-\frac{7}{3}}
Since \frac{16}{7} and \frac{9}{7} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{7}{7}}{\frac{5}{4}-\frac{7}{3}}
Subtract 9 from 16 to get 7.
\frac{1}{\frac{5}{4}-\frac{7}{3}}
Divide 7 by 7 to get 1.
\frac{1}{\frac{15}{12}-\frac{28}{12}}
Least common multiple of 4 and 3 is 12. Convert \frac{5}{4} and \frac{7}{3} to fractions with denominator 12.
\frac{1}{\frac{15-28}{12}}
Since \frac{15}{12} and \frac{28}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{-\frac{13}{12}}
Subtract 28 from 15 to get -13.
1\left(-\frac{12}{13}\right)
Divide 1 by -\frac{13}{12} by multiplying 1 by the reciprocal of -\frac{13}{12}.
-\frac{12}{13}
Multiply 1 and -\frac{12}{13} to get -\frac{12}{13}.