Solve (4+8)^2-(4/2)^2+10+(-10+2)-(-5*2)+2800

$$( 4 + 8 ) ^ { 2 } - ( \frac { 4 } { 2 } ) ^ { 2 } + 10 + ( - 10 + 2 ) - ( - 5 \times 2 ) + 2800$$

Evaluate

$$2952$$

Solution Steps

Add 4 and 8 to get 12.

$$12^{2}-\left(\frac{4}{2}\right)^{2}+10-10+2-\left(-5\times 2\right)+2800$$

Calculate 12 to the power of 2 and get 144.

$$144-\left(\frac{4}{2}\right)^{2}+10-10+2-\left(-5\times 2\right)+2800$$

Divide 4 by 2 to get 2.

$$144-2^{2}+10-10+2-\left(-5\times 2\right)+2800$$

Calculate 2 to the power of 2 and get 4.

$$144-4+10-10+2-\left(-5\times 2\right)+2800$$

Subtract 4 from 144 to get 140.

$$140+10-10+2-\left(-5\times 2\right)+2800$$

Add 140 and 10 to get 150.

$$150-10+2-\left(-5\times 2\right)+2800$$

Subtract 10 from 150 to get 140.

$$140+2-\left(-5\times 2\right)+2800$$

Add 140 and 2 to get 142.

$$142-\left(-5\times 2\right)+2800$$

Multiply -5 and 2 to get -10.

$$142-\left(-10\right)+2800$$

The opposite of -10 is 10.

$$142+10+2800$$

Add 142 and 10 to get 152.

$$152+2800$$

Add 152 and 2800 to get 2952.

$$2952$$

Factor

$$2^{3}\times 3^{2}\times 41$$