Solve (4+1/3)(n-1/3)

$$( 4 + \frac { 1 } { 3 } ) ( n - \frac { 1 } { 3 } )$$

Evaluate

$$\frac{13n}{3}-\frac{13}{9}$$

Solution Steps

Convert 4 to fraction \frac{12}{3}.

$$\left(\frac{12}{3}+\frac{1}{3}\right)\left(n-\frac{1}{3}\right)$$

Since \frac{12}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{12+1}{3}\left(n-\frac{1}{3}\right)$$

Add 12 and 1 to get 13.

$$\frac{13}{3}\left(n-\frac{1}{3}\right)$$

Use the distributive property to multiply \frac{13}{3} by n-\frac{1}{3}.

$$\frac{13}{3}n+\frac{13}{3}\left(-\frac{1}{3}\right)$$

Multiply \frac{13}{3} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{13}{3}n+\frac{13\left(-1\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{13\left(-1\right)}{3\times 3}.

$$\frac{13}{3}n+\frac{-13}{9}$$

Fraction \frac{-13}{9} can be rewritten as -\frac{13}{9} by extracting the negative sign.

$$\frac{13}{3}n-\frac{13}{9}$$

Expand

$$\frac{13n}{3}-\frac{13}{9}$$

Solution Steps

Convert 4 to fraction \frac{12}{3}.

$$\left(\frac{12}{3}+\frac{1}{3}\right)\left(n-\frac{1}{3}\right)$$

Since \frac{12}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{12+1}{3}\left(n-\frac{1}{3}\right)$$

Add 12 and 1 to get 13.

$$\frac{13}{3}\left(n-\frac{1}{3}\right)$$

Use the distributive property to multiply \frac{13}{3} by n-\frac{1}{3}.

$$\frac{13}{3}n+\frac{13}{3}\left(-\frac{1}{3}\right)$$

Multiply \frac{13}{3} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{13}{3}n+\frac{13\left(-1\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{13\left(-1\right)}{3\times 3}.

$$\frac{13}{3}n+\frac{-13}{9}$$

Fraction \frac{-13}{9} can be rewritten as -\frac{13}{9} by extracting the negative sign.

$$\frac{13}{3}n-\frac{13}{9}$$